Solution:
Will use dp strategy.Define dp[l][r] as the max gain for one player comparing with his opponent in the range from l to r.
Code:
class Solution {
public:
bool PredictTheWinner(vector<int>& nums) {
int n = nums.size();
vector<vector<int>> dp(n, vector<int>(n, 0));
for(int l=n-2; l>=0; --l){
for(int r=l+1; r<n; ++r){
dp[l][r] = max(nums[l]-dp[l+1][r], nums[r]-dp[l][r-1]);
}
}
return dp[0][n-1]>=0;
}
};
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